let x and y be whole numbers greater than 0 with y > x. which has the greater value, 3^x or 3^y? explain
Let u = (3^y) / (3^x)
Then u = 3^(y-x)
i.e. u = 3^z, where z = y - x
since y > x and x,y whole numbers,
then z is a whole number
Since z is a whole number, then u = 3^z > 1
i.e. u = (3^y) / (3^x) > 1
or, 3^y > 3^x