(4-3i/7)+2/7+8i-(4-2i)

Evaluate and write its conjugate
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1 Answer

(4-3i/7)+2/7+8i-(4-2i)

4 - 3i/7 + 2/7 + 8i - 4 + 2i

4 + 2/7 - 4 - 3i/7  + 8i + 2i

2/7 + i(10 - 3/7)

(1/7)(2 + 67i)

The complex number evaluates to: 2/7 + 67i/7

The complex conjugate of the number (a + bi) is (a - bi).

The complex conjugate of the above solution is: 2/7 - 67i/7

by Level 11 User (81.5k points)

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