simplify secΘ ctnΘ

i need the answers to a couple of equations

can someon simplify the following:

sinx(1+ctn^2x)

ctn^2x/1+ctn^2x

sinA/tanA - tanA/secA

secY cosY - cos^2Y
in Trigonometry Answers by

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1 Answer

Best answer
secA*ctnA=1/cosA * cosA/sinA = 1/sinA = cscA

sexA = 1/cosA an ctnA = cosA/sinA
by Level 8 User (36.8k points)

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