What is the sum of 4 consecutive intergers whose sum is 80

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What is the sum of 4 consecutive intergers whose sum is 80

let x = the smallest consecutive number

x + (x+1) + (x+2) + (x+3) = 80

x + x+1 + x+2 + x+3 = 80

4x + 6 = 80

4x = 74

x = 18.5

18.5, 19.5, 20.5, and 21.5

Check

18.5 + 19.5 + 20.5 + 21.5 = 80

 

by Level 6 User (19.3k points)

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