A father is 30 years older than his son. In ten years times he will be three times as old as his son. Calculate the present age of each one
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1 Answer

A father is 30 years older than his son. In ten years times he will be three times as old as his son. Calculate the present age of each one

Let F = father's current age

Let S = son's current age

Then,

F = S + 30        (A father is 30 years older than his son)

Now add on 10 years, giving

F + 10 = 3(S + 10)      (In ten years times he will be three times as old as his son.)

Substituting for F = S + 30,

(S + 30) + 10 = 3(S + 10)

S + 40 = 3S + 30

10 = 2S

S = 5, F = 35

by Level 11 User (81.5k points)

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