How to find original number please
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The sum of the digits of a two -digit number is 14. When the digits are reversed the difference between the original number and the new number is 36. find the original number

Let the number be N and the two digits comprising the number be a and b.

Then we can write the number N as ab.

We can also write the value of N as N = 10*a + b

Let the new number be M such that M = ba (the digits are reversed)

Now the can write the value of M as M = 10*b + a

We also have M - N = 36   (the difference between the original number and the new number is 36)

OR,                N - M = 36   (the difference between the original number and the new number is 36)

Using, M - N = 36

10b + a - (10a + b) = 36

9b - 9a = 36

b - a = 4

But, a + b = 14   (sum of digits is 14)

Adding these two equations,

2b = 18

b = 9, therefore, a = 5

Answer: N = 59

​N = 95 is also a possibility, (We would have got this if we had used N - M = 36)

by Level 11 User (81.5k points)

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