2

8x-x        =0  

 

 

just pretend that 2 is closer to the 'x'..it's supposed to be x SQUARED

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1 Answer

Problem: what is the value of x in the equation 8x-xsquared=0???

8x - x^2 = 0
8x - x^2 + x^2 = 0 + x^2
8x - x^2 + x^2 = 0 + x^2
8x = x^2
8x/x = (x^2)/x
8 = x

Answer: x = 8; it is also 0

8x = x^2
8*8 = 8*8
64 = 64

8x = x^2
8*0 = 0*0
0 = 0

 

by Level 11 User (78.4k points)

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