differential calculus
asked Dec 10, 2016 in Calculus Answers by anonymous

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(1) y'=x^2+x+1/4

(2) y'=2(x^-2+x^2)=2(-2x^-3+2x)=-4/x^3+4x=4(x-1/x^3)

(3) y'=(1/3)(2x^3-3/x^3)^(-2/3)(6x^2+9/x^4)=






(4) Let a=2^(1/3); y=ln(a^3x^3)=3ln(ax); y'=(3/ax)a=3/x

(5) y'=((e^x)sinx-(e^x)cosx)/(sinx)^2=(e^x)(cosecx-cotxcosecx)

answered Dec 10, 2016 by Rod Top Rated User (486,780 points)
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