(2x) ^1/2 * (3x) ^2 /3.. 1/2 is a power to 2x and 2/3 is a power to 3x. So the 2x in bracket and its power multiply with the 3x in bracket and its power.

Question

The (2x) and its power 1/2 will be multiply with (3x) and its power.

Answer 1

(2x)^1/2 * (3x)^2/3 = 2^1/2 *   x^1/2*3^2/3 * x^2/3 =2^1/2 * 3^2/3 * x*(1/2+2/3) =

2*1/2 * 3* 2/3 * x^7/6 = sqrt2 * ( 3th root of 9) *( 6th root of x^7 )=

sqrt2 * ( 3th root of 9) *x* (6th root of x) 0r

= 2*1/2 *  9 ^ 1/3 *x * x^1/6