how do i solve

6(x+4)=8(x-2)
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1 Answer

6(x + 4) = 8(x - 2)
 
First you can multiply out the brackets:
 
6(x + 4) = 8(x - 2)
6(x) + 6(4) = 8(x) - 8(2)
6x + 24 = 8x - 16
 
Now you can add 16 to both sides of the equation:
 
6x + 24 + 16 = 8x - 16 + 16
6x + 40 = 8x
 
Now you can subtract 6x from both sides of the equation:
 
6x + 40 - 6x = 8x - 6x
40 = 2x
 
Now divide by 2 for both equations:
 
40/2 = (2x)/2
20 = x
 
And so the final solution is: x = 20         smiley
by Level 5 User (10.2k points)
edited

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