2 sin^2 - sin x= 0,x= 0

Question

how do i slove that problem ?

Answer 1

2 sin^2 - sin x=

sinx(2 sinx - 1)= 0

sinx = 0 ⇒ x = 0, pi, 2pi

and 2sinx - 1 = 0

sinx = 1/2 ⇒ x = pi/6                   [( sin(pi/6) = 1/2]