Problem: 126=(x+3)(x)(2)
i need help figuring this out i am stumped
126 = (x + 3)(x)(2)
(x + 3)(x)(2) = 126 :: convention has the unknowns on the left side
(x^2 + 3x)(2) = 126
2x^2 + 6x = 126
x^2 + 3x = 63
x^2 + 3x - 63 = 0
-b ± sqrt(b^2 - 4*a*c)
x = -----------------------------
2a
-3 ± sqrt(3^2 - 4*1*(-63))
x = ----------------------------------
2(1)
-3 ± sqrt(9 - (-252))
x = ------------------------------
2
-3 ± sqrt(261)
x = ----------------------
2
-3 ± 16.155
x = ------------------
2
-3 + 16.155 -3 - 16.155
x = ------------------ and x = ------------------
2 2
13.155 -19.155
x = ----------- and x = --------------
2 2
x = 6.5775 and x = -9.5775