rectangle area= 88 inches, length= 12 inches longer than its width, Find the dimensions of this sign?
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If w=width, then length=w+12, so area in square inches=88=w(w+12).

w^2+12w=88; w^2+12w+36=88+36 (completing the square);(w+6)^2=124; w+6=+sqrt(124)=+2sqrt(31)=+11.14.

So w=11.14-6=5.14" and length=17.14" (the other solution is negative, so can be ignored).

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