In triangle ABC <A=75°,<B=34°,the length of a,of the side opposite angle A is 10.2cm .Find the length b,of the side opposite angle B
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In triangle ABC <A=75°,<B=34°,the length of a,of the side opposite angle A is 10.2cm .Find the length b,of the side opposite angle B

All we need to do here is use the sine rule. Which is ...

a/sin(A) = b/sin(B)

We have: a = 10.2 cm, A = 75, b = ?, B = 34.

Therefore,  10.2/sin(75) = b/sin(34)

b = 10.2*(sin(34)/sin(75)) = 10.2*(0.55919/0.96592) = 10.2*0.57892

b = 5.90497

Answer: b = 5.9 cm

by Level 11 User (81.5k points)

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