how many liters of 100% pure acid should be used to make the solution?
asked Oct 20, 2015 in Algebra 1 Answers by joe

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A=amount of 100% acid and X=amount of 5% acid solution. A+X=95 (equating amounts of liquid) and A+X/20=16/100*95=16*19/20 (equating amounts of acid present in each liquid).

Multiply last equation through by 20: 20A+X=304. Subtract first equation: 19A=304-95=209, A=209/19=11L and X=95-11=84L. So 11L of pure acid needs to be added to 84L of 5% acid solution to produce 95L of 16% acid solution.

answered Oct 20, 2015 by Rod Top Rated User (582,800 points)

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