Problem: y=2/3x+9; (-6,5)
parellel and perpendicular lines
The point (-6, 5) is on the given line:
y = 2/3 x + 9
y = 2/3 (-6) + 9
y = -4 + 9
y = 5
Therefore, we must be looking for the
equation of a perpendicular line. For that,
we use the negative inverse of the slope.
-(1/(2/3)) = -3/2
We need the y-intercept for the new equation.
y = mx + b
y - mx = b
Use the x and y co-ordinates of the specified point.
b = y - mx
b = 5 - (-3/2)(-6)
b = 5 - 9
b = -4
The equation is y = -3/2 x - 4