I have 2 cubes.  I roll each cube one time.  What is the probability that one cube land on a even number and the second one land with a number greater than 2
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6 sides=6 digits...1, 2, 3, 4, 5, 6...chans av even=50%

1 side sae > 2...meen anser=3, 4, 5, 6....4 out 6....2/3  or 66%
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The odd numbers are 1, 3 and 5 and the evens 2, 4 and 6, so there's 3/6=1/2 chance of rolling an even number. Numbers greater than 2 are 3, 4, 5 and 6, so that's 4/6 or 2/3 chance of rolling a number greater than 2. Combined probability: 1/2*2/3=1/3 of rolling an even number first and then a number greater than 2 on the second roll.

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