Problem: what is the answer to 4y=12y squared
I dn't know to work this problem
4y = 12y^2
12y^2 = 4y
12y^2 - 4y = 0
12y^2 - 4y + 0 = 0 included + 0 to show c in the quadratic formula
-b ± √(b² - 4*a*c)
y = --------------------
2a
-(-4) ± √((-4)² - 4*12*0)
y = -------------------------------
2(12)
4 ± √(16² - 0)
y = -----------------
24
4 ± √(16²)
y = -----------------
24
4 ± 4
y = ---------
24
4 + 4 4 - 4
y = --------- and y = ---------
24 24
8 0
y = --------- and y = ---------
24 24
y = 1/3 and y = 0
Check both values.
4y = 12y^2
4(1/3) = 12(1/3)^2
4/3 = 12(1/9)
4/3 = 4(1/3)
4/3 = 4/3
4y = 12y^2
4(0) = 12(0)^2
0 = 12(0)
0 = 0
Answer: y = 1/3, y = 0