4y^2-8y=x-2

Question

I am trying to graph this conic parabola. I get to this part 4(y-1)^2=x+2 and i get stuck

Answer 1

4y^2-8x+2=x

thank av it as parabola along x axis insted av y

or chaenj symbols...4x^2-8x+2=y

become y=(x-1.707106781)*(x-0.292893219)...parabola with vertikal axis

thru bottom point=(1.707106781, 0.292893219)

So original=parabola  with horizontal axis & interchaenj x with y