How to figure out what  the varible  x in the equation 4x(x-8)-5x(x-7)=-4 would be?
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4x (x-8) - 5x (x-7) = -4 original line

4x^2 - 32x - (5x^2 - 35x) = -4 multiply out the two brackets with the outside of the brackets

4x^2 -32x - 5x^2 + 35x = -4 take out the second bracket fully by timesing by negative (swapping signs)

-x^2 +3x +4 = 0 gathering all terms together and adding 4 to both sides

(-x+4) (x+1) factorising.  

x= -4 or x=-1 as each bracket must =0.  Could also complete the square or use the quadratic formula if you know how, you will get the same answer though.
by Level 3 User (4.6k points)

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