The height of a parallelogram is 5 feet more than its base. If the area of parallelogram is 204 square feet, find its base and height.
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2 Answers

parallelogram...area=base*hite=204

hite=base+5, so area=(base+5)*base

=base^2+5base=204

or in standard math, yu hav x^2+5x-204=0

quadratik equashun giv roots=12 & 17...12*17=204
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The problem states: x * (x + 5) = 204

Perform the multiplication on the left side: (x * x) + (5 * x) = 204       x * x, x squared, is x^2

Subtract 204 from both sides of the equation: x^2 + 5x - 204 = 204 - 204 = 0

We have x^2 + 5x - 204 = 0

Factor the equation on the left side: (x + a) * (x - b) = 0      a and b used for illustration

One of them has to be negative so we get -204 when they are multiplied together  (a * -b) = -204

One of them has to be 5 larger than the other so when we add ax to -bx we get 5x

Factors of 204 that satisfy the requirements are 17 and 12

(x + 17) * (x - 12) = 0

One of the quantities has to be zero to produce a zero from the multiplication

x + 17 = 0       x = -7      a side -7 feet long is not likely in the real world

x - 12 = 0       x = 12

This satisfies the original statement that one side is 5 feet longer than the other; one is 12 feet the other is 17 feet
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