2x^2+7x-25=11      2x^2+7x-25-24=24-24        2x^2+7x-49=0    2(x+7)(x-7) +7x=0    answer being (x+7)(x-7)  or do I take it further ?
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2 Answers

2x^2+7x-25=11
2x^2+7x-36

just use the quadratic formula,
((-b-sqrt(b^2-4ac)/(2a)
((-b+sqrt(b^2-4ac)/(2a)

you should get (2.839 and -6.339)
by Level 5 User (14.8k points)
How did 2x^2 + 7x - 25 = 11 even become 2x^2 + 7x - 25 - 24 = 24 - 24 in the first place? In your first equation, the right hand side is 11, but in your second equation, it has somehow became 24.

For your second part, (x + 7)(x - 7) is definitely not the solution. You are ignoring the additional 7x completely.

 

2x^2 + 7x - 25 = 11
2x^2 + 7x - 25 - 11 = 0
2x^2 + 7x - 36 = 0
(2x^2 + 7x) - 36 = 0
2(x^2 + (7/2)x) - 36 = 0
2(x + (7/4))^2 - 49/8 - 36 = 0
2(x + (7/4))^2 - 337/8 = 0
2(x + (7/4))^2 = 337/8
(x + (7/4))^2 = 337/16
x + 7/4 = sqrt(337/16) or = -sqrt(337/16)
x = -7/4 + sqrt(193/8) or x = -7/4 - sqrt(193/8)

 

Suppose you meant  2x^2 + 7x - 25 = 24 instead. We have:

2x^2 + 7x - 25 - 24 = 0
2x^2 + 7x - 49 = 0
(2x^2 + 7x) - 49 = 0
2(x^2 + (7/2)x) - 49 = 0
2(x + (7/4))^2 - 49/8 - 49 = 0
2(x + (7/4))^2 - 441/8 = 0
2(x + (7/4))^2 = 441 / 8
(x + (7/4))^2 = 441 / 16
x + 7/4 = sqrt(441/16) or = -sqrt(441/16)
x = -7/4 + sqrt(441/16) or x = -7/4 - sqrt(441/16)
x = -7/4 + (21/4) or x = -7/4 - (21/4)
x = 14/4 or x = -28/4
x = 7/2 or x = -7
by

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