2^a x a^2 = 4147a where a is the digit in ones place, find a

Question

Given that                 2^a x a^2 = 4147a                  where a is the digit in ones place, find a

Answer 1

????? me dont understand wot yu tri tu sae ????

?? maebee "a" be a 1-digit number...0, 1, 2, ...9

?? then yu multipli 2 terms tugether ???

term1=2^a & term2=a^2 ??? & result=4147???

if 1 digit, biggest value for a=9

term1....2^9=512

term2...9^2=81 & then term1*term2=41,472

tri a=5...term1=2^5=32, term2...5^2=25, times=800

tri a=7...term 1=2^7=128, term2...7^2=49, 49*128=6,272

tri a=6...term1=2^6=64, term2...6^2=36, 36*64=2,304

me dont get 4147