2x^3+16x^2+32x=0

Please show step by step.

It seems I'm able to get part of the answer (-4) but not the other part (0)

This is how I did it, I factored it first:

2x(x^2+8x+16)=0, then factored it again

(x+4) (x+4) but this is wrong because then I did

x+4=0  |  x+4=0

(I minus -4 on both sides of the =  sign for the left equation and the right equation; and get (-4) for both of them, but the correct answer is (0) & (-4)

 Please help. Thanks.
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1 Answer

4x^2-32x+16=0
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