Quadratic equations

Question

X²-4X-12=0

Answer 1

x^2 - 4x - 12 = 0

ask yourself what multiplies to make 12 and subtracts to make 4

that would be 6 and 2

therefore (x-6)(x+2) = 0

set each = 0

x - 6 = 0 so x = 6

x+2 = 0 so x = -2

Answer 2

Solve the quadratic eq (y/y+1)+(y+1/y)

Answer 3

x^2-4x-12    using formular method,   x= (-b)+_ squareroot of b^2-4ac /2a            in this equation,a=1, b=-4 , c=-12    x=-(-4)+_squareroot(-4)^2 -4×1×(-12) /2×1    x=4+_ squareroot 16+48 /2   x=4+_squareroot64 /2       x=4+_8 /2     x=4+8 /2 or x=4-8 /2   x=12/2 or x=-4/2       :.x is either 6 or -2

Answer 4

(x-6)(x+2)

Answer 5

(2x-1)² = (x+1)²

Answer 6

(x+2)(x-6)=0

x+2=0, x-6=0

x=-2 or x=6