What is the greatest possible whole number remainder of any number divided by 41

Question

Whole number problems

Answer 1

????????????????? "hole number ???????? me numbers DONT hav holes

??????????????? "remaender" ???????? wotz zat?????????

yu must meen LEFTOVER

x/41 ???????

???????????? yu tri tu impli x gota be INTEGER ???????????

me thank yu talk bout the MOD funkshun

mod(1,41)=1

mod(2,41)=2

mod(5,41)=5

mod(40,41)=40

Answer 2

The largest remainder possible will always be 1 less than the divisor (in this case 40) as you cannot have a remainder equal to the divisor, otherwise it would divide exactly and the remainder would be zero.