Caramels costing $3.75 per pound are mixed with chocolates costing $3 per pound to make a 6 pound mixture that will be sold at $3.25 per pound. How many pounds of each are needed?
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1 Answer

Percentage problems
Caramels costing $3.75 per pound are mixed with chocolates costing $3 per pound to make a 6 pound mixture that will be sold at $3.25 per pound. How many pounds of each are needed?

3.75x + 3y = 3.25
x + y = 1

x = 1 - y

3.75x + 3y = 3.25
3.75(1 - y) + 3y = 3.25
3.75 - 3.75y + 3y = 3.25
-0.75y = -0.5
y = 0.666 = 2/3

x + 2/3 = 1
x = 1/3

To make 1 lb of the mixture requires 1/3 lb of the caramels and 2/3 lb of the chocolates.
To make 6 lbs of the mixture requirs 6 * 1/3 lb = 2 lbs of the caramels and 6 * 2/3 lb = 4 lbs of the chocolates.

Check.

3.75x + 3y = 3.25
3.75(1/3) + 3(2/3) = 3.25
1.25 + 2 = 3.25

Answer: 2 lbs of the caramels, 4 lbs of the chocolates to make 6 lbs of the mixture

 

by Level 11 User (78.4k points)

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