solve using the quadratic forula
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1 Answer

3x squared= 6x-1

3x^2 - 6x + 1 = 0

 

         - (- 6) +/- sqrt( (-6)^2 - 4*3*1)      6 +/- sqer(36 - 12)

x = ----------------------------------------- = ---------------------------

                2*3                                                     6

        6 +/- sqrt(4*6)       6 +/- 2sqrt6

x = -------------------- = -------------------

            6                              6   

x = ( 6 + 2sqrt6)/6 = (3 + sqrt6)/3    and

x = (6 - 2sqrt6)/6 = ( 3 - sqrt6)/3

                       

by Level 8 User (36.8k points)

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