1.      2csc2 A – 32

2.      3cot2 B – 27

3.      Sin2 Ө – 18sin Ө + 81

4.      5cos3 w – 15

5.      Cot3 Ө + 2cot2 Ө + cot Ө

 

 

So this is Factoring trigonometric functions

 

Anyone who knows how to solve this?

MANY MANY MANY MANY MANY thanks to anyone who can solve this. 

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1 Answer

 2csc2 A – 32 =                  3cot2 B – 27 =

                                         3(cot^2 - 9)=

(2csc^2 - 32) =                 3( cot^2 - 3^2)

2(csc^2 - 16 )=                3( cot - 3)( cot + 3)

2(csc^2 - 4^2) =

2(csc - 4)( csc + 4)

 

Sin2 Ө – 18sin Ө + 81 = ( sin - 9)( sin - 9)

5cos3 w – 15 = 5(cos^3 - (3^(1/3))^3=

5(cos - 3)( cos^2  + 3^(1/3)*cos + 3^(1/3)^2 )

by Level 8 User (36.8k points)
Thank you so much sir! :)

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