Sin ^2 120^o + cos ^2 120 ^o

Question

Please help me 

1.  Sin 

Answer 1

?????? iz zat spozed tu be sine^2 av 120^0 ????????

me see yu sho 120^ letter o, not the digit zero

me gonna assume yu meen zero

120^0=1

sine(1 deg)=0.01745240643728351

kosine(1 deg)=0.9998476951563913

Answer 2

[Sin(90+30)]^2+[cos(90+30)]^2= [cos 30]^2+[-sin 30]^2= (sqrt(3)/2)^2+(-1/2)^2 = 3/4+1/4 =1