Need to solve for t in ; r= 1/3 d(60-t)
in Algebra 1 Answers by Level 1 User (160 points)

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2 Answers

r=(1/3)*d*(60-t) & yu want t

(60-t)=3r/d

-t=(3r/d)-60

t=60-(3r/d)
by

Given r= 1/3 d(60-t)
r=d(20-t/3)
20-t/3=r/d
-t/3=r/d-20
t/3=(20-r/d)
t=3[20d-r]/d

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by Level 8 User (30.1k points)

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