Let unknown 2 numbers be x and y (x>y). This problem can be written as follows:
x=y+6 ··· (1), and xy=18 ··· (2) Plug (1) into (2), getting
(y+6)y=18 Put the equation into quadratic standard form, getting
y²+6y-18=0 Using quadratic formula, solve the equation for y. We have:
y=(-6±√(36+72))/2=(-6±6√3)/2=-3±3√3 Plug the values of y into (1). We have:
x=(-3±3√3)+6=3±3√3
Therefore, the answer is: { x=3+3√3, y=-3+3√3 }, or { x=3-3√3, y=-3-3√3 }