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how do you solve by compleing the square?

You have an equation such as ax^2 + bx + c = 0.

Move the c term to the right side of the equation,
by addition or subtraction: ax^2 + bx = -c.

Divide by the co-efficient of the x^2 term: x^2 + b/a x = -c/a

Take half of the x co-efficient and square it:  ((b/a) / 2)^2 = (b/2a)^2

Add that to both sides of the equation: x^2 + b/a x + (b/2a)^2 = -c/a + (b/2a)^2

You can easily factor the left side of the equation: (x + b/2a)(x + b/2a)

The equation is now: (x + b/2a)(x + b/2a) = -c/a + (b/2a)^2

Take the square root of both sides: (x + b/2a) = ±√ [-c/a + (b/2a)^2]

Move the b/2a constant to the right side of the equation, again
by either addition or subtraction: x = ±√ [-c/a + (b/2a)^2]  - b/2a

Remember that the square root you obtained on the right side of the
equation must be a positive value and a negative value. In the end,
you have two equations for x:

x = √ [-c/a + (b/2a)^2]  - b/2a       and     x = -√ [-c/a + (b/2a)^2]  - b/2a
by Level 11 User (78.4k points)
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