Equation of a circle
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1 Answer

(x-3)^2=x^2-6x+9

(y+4)^2=y^2+8y+16

so, (x^2-6x) +(y^2+8y)=11  become (x-3)^2 +(y+4)^2=11+25=36

serkel with senter a (3,-4) & wide=6
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