Solve: 3x-4y=7(2x-y), 5x-3y+3=0

Question

Solve the following simultaneous equations.

3x-4y=7(2x-y), 5x-3y+3=0

Answer 1

line 1...3x-4y=7(2x-y) become 3x-4y=14x-7y...14x-3x=7y-4y...11x=3y...x=(3/11)y

line 2...5x-3y=-3...5x=3y-3...x=(3/5)*(y-1)

(3/5)*(y-1)=(3/11)y

(33/5)*(y-1)=3y...(33/5)y -(33/5)-3y=0

[(33/5)-3]y=(33/5)   or (6.6-3)y=6.6

3.6y=6.6....y=6.6/3.6=1.8333333333333333...

from line 2... 5x=3y-3=5.5-3=2.5

x=2.5/5=0.5

Answer 2

Given 3x-4y=7(2x-y).......(1)
5x-3y+3=0......(2)

Substitute y=5x/3+1 value from equation(2) to equation (1)
3x-4(5x/3+1)=7(2x-(5x/3+1))
x=1/2

Substitute x value in equation (1)
5(1/2)-3y+3=0
y=11/6

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