y=-0.3476x²+10.498x-23.078 how do you solve for x when y is 47

Need to know how to solve for x
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1 Answer

me spekt yu got it bakward & need tu EVALUATE y at x=47

y=-0.3476 x^2+10.498x -23.078

at x=47, x^2=2209 & -0.3476x=-767.8484

10.498x=10.498*47=+493.406

add 3 terms...-767.8484 -23.078+493.406...-297.5204

##### if yu reelee want y=47, yu gotta tri variee x's & home tu iterate tu sumthun that come kloes

me get x=9.90111

look at x=10...x^2=100 & -0.3476*x^2=-34.76

10.498*x=10.498*10=+104.98

104.98-34.76 -23.078...+47.142...pretty kloer tu 47
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