Question

a polygon have 5 right angleand remaining angle are 195 each find the no of sides of polygon.

Answer 1

First, I drew the polynomial:

there are 12 sides!

Answer 2

let the number of sides of the polygon be n. therefore the sum of the interior angles of a polygon with sides n is (n-2)* 180. it is given that there are 5 right angles and remaining angles are equal to 195. therefore sum of interior angles = 5*90+(n-5)*195 hence thus the polygon has 11 sides.

Answer 3

n =no of sides (n-2)*180= sum of interior angles 5 right angles ;5*90 (n-2)180=5*90+(n-5)195 180-n-360=450+195n-975 15n=165 n=11 answer