factorise p(x) and find b

Question

if p(x)=2x^3+x^2+bx-6 leaves a remainder 36, when divided by x-3, find the value of b and with value of b, factorise p(x)

Answer 1

Given p(x)=2x^3+x^2+bx-6

Since x-3 leaves a remainder of 36,
p(3)=2(3)^3+(3)^2+b(3)-6
p(3)= -19
p(x)=2x^3+x^2-19x-6

Factor
(x-3)(2x^3+7x+2)