show that 1903<(√13+3)^4<1904

Cannot use calculator or tables Hint expand (a^2+b^2)^2
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1 Answer

me kan yuze kalkulater...sqrt(13)=3.60551275463989

+3 make it 6.6055...

that ^4=1,903.8655367224935

[3+sqrt(13)]^2 =24+6*sqrt(13)

square agin & yu gt 576+468 +12*sqrt(13)....1044+12*sqrt(13)

12*3.6055127...=43.26661530556787

add 1044 & yu get 1,087.266615305568

me trust kalkulater
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