how to solve the equation x/x-4 + x-3/x-4 =??/x-4

Question

x/x-4 + x-3/x-4= ??/x-4

Answer 1

mi ges be yer junk shood be

x/(x-4) +(x-3) / (x-4) =y/(x-4)

thus, x+x-3=y

y=2x-3

Answer 2

When you add fractions with the same denominator, use the rule shown below:

b/a + c/a = (b+c)/a , a≠0. (subtraction: b/a - c/a = (b-c)/a)

Here, a = x-4, b = x, c = x-3   Therefore,

x/(x-4) + (x-3)/(x-4) = {x + (x-3)}/(x-4) = (x+x-3)/(x-4) = (2x-3)/(x-4)

The answer is: (2x-3)/(x-4)*

* the improper form: (2x-3)/(x-4)=(2x-8+5)/(x-4)={2(x-4)+5}/(x-4)=2(x-4)/(x-4) + 5/(x-4)=2 and 5/(x-4)