...as the fourth power of it's diameter, d, and the square of the number, n, of revolutions per second.

What happens to the thrust if n is doubled and d is halved?
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1 Answer

T=k*d^4*RPM^2

d kut in half & RPM dubel

yu get (1/2)^4*2^2

or (1/2)^2....1/4
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