Write the equation of the line that is perpendicular to 2x – 3y = 9 and contains the point (–6, 12).
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1 Answer

First thing is to find the slope of the perpendicular line.

Slope of 2x -3y = 9

-3y = 9 - 2x

y = -3 +(2/3)x

y = (2/3)x - 3

slope = 2/3

Perpendicular is opposite sign, flipped fraction

slope perpendicular = -3/2

...contains the point (-6,12)

point-slope form...

y - y1 = m (x - x1)

y - 12 = (-3/2) (x + 6)

y - 12 = (-3/2)x - 9

y = (-3/2)x + 3
by Level 13 User (103k points)

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