Problem: Whatare two possible coordinate pairs that could be the location of the third vertex
Triangle has a hypotenuse that is 26 units. The end points is base are located at (-2,5) and (3,5).
The distance from (-2, 5) to (3, 5) is 5.
Using the formual a^2 + b^2 = c^2:
a^2 + 5^2 = 26^2
a^2 + 25^2 = 676
a^2 = 676 - 25
a^2 = 651
a = 25.5147 We can ignore the negative square root
There are four possible endpoints. Side a can run up from
side b, or it can run down from side b. Also, it can attach
to the left endpoint of side b, or it can attach to the right
endpoint of side b.
Using only the left endpoint, the two possible locations are:
(-2, (5 + 25.5147)) and (-2, (5 - 25.5147))
(-2, 30.5147) and (-2, -20.5147)