If the initial value of a sequence is 6 and the common difference is 6, what is the 18th element?
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t(6) = a + (n-1)d a + 5d = 71---------eqn(1) t(18) = a + 17d a + 17d = 29 ---------eqn(2) subtracting (1) from (2) 12d = -42 the common difference, d = - 42/12
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