simplify (x^3-y^3)/(3x^2+xy-4y^2)*(3x^2+7xy+4y^2)/x^2+xy+y^2)

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1 Answer

x^3-y^3=(x-y)*(x^2+xy+y^2)

3x^2+xy-4y^2=(3x+4y)*(x-y)

3x^2+7xy+4y^2=(3x+4y)*(x+y)

So simplify (x^3-y^3)/(3x^2+xy-4y^2)*(3x^2+7xy+4y^2)/x^2+xy+y^2) is "x+y"

by Level 1 User (180 points)

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