(x + 1)(x + 4) < 0

Question

Solve and graph on a number line.

Answer 1

first, look at kerv...(x+1)*(x+4)=o...or x^2 +5x+4=0

=parabola that go thru points: (-1,0) & (-4,0)

hav x^2, so yuno it go up (vertikal axis)

<0 impli yu want area belo parabola

dy/dx=2x+5=slope & slope=0 at 2x=-5...or x=-2.5...thats bottom av parabola

Answer 2

 

___+___  -4  ____-_____-1_____+_____

 )-4;-1(