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Question: Find an exponential function given the points (2,3);(5,1/9) .

When you are told that you have an exponential function, then you may assume that it is of the form,

y = k.a^x

where x and y are your independent and dependent variables and k and a are two unknown constant values.

Since you are given two sets of values for x and y (the coordinate points) then you will be able to create a pair of simultaneous equations that you can solve for the unknown constnts.

The point (x,y) = (2,3)

3 = k.a^2    ------------------------------- (1)

The point (x,y) = (5,1/9)

1/9 = k.a^5     --------------------------- (2)

Divide (1) by (2).

27 = a^(-3)

27 = 3^3 = a^(-3)

3 = a^(-1)

a = 1/3 = 3^(-1)

Substituting for a = 3^(-1) into (1),

3 = k.(3^(-1))^2 = k.3^(-2)

k = 27

This gives the equation as: y = 27.3^(-x) = 3^3.3^(-x) = 3^(3-x)

Answer: y = 3^(3-x)

by Level 11 User (81.5k points)

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