estimate image using differential

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1 Answer

sqrt[(3/2)^2 +(1/92)^2 +3*(0/96)^2]

0/96=0 & 3*0=0, so yu hav

sqrt[(1.5)^2 +(1/92*92)]

=sqrt[2.25 +(1/8464)]

=sqrt(2.25+0.00011814744801512287)

=sqrt(2.250118147448015)

=1.500039381965692
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