Plz plz help on power

a machine of an IMA of 5 is used by a man to lift a load of 500N by appling a 125N force at 3m/s.If the machine is ideal calculate the input and output power developed
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125 newtons*(3 meter/sekond)=375 newton-meter per sek

1 newton=0.1019716 kilogram foers

=38.23935 kilogram-(meter/sek)

1 kgf-met/sek=9.8066 watt

so yu put out 374.998 watts

or 1 watt=0.001341 hoerspower, so 374.998 become -/6-398344 jprtd[pert
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