I am so lost I do not know what to do someone help me
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2 Answers

3ax/3a=x

so the first part become x^2 +x -x...x^2

sekond part...me assume that stuf shood be x^2 -4ax +3ax^2

become (x-3a)*(x-a)

anser...x^2*(x-3a)*(x-a)
by

The dollar sign, $, must be a misprint.   Replace it with a round bracket, ).  The question can be rewritten and simplified as follows:

{(x²+3ax) / (3a-x)}·(x²-4ax+3a²) = {x(x+3a) / (3a-x)}·{(x-3a)(x-a)} =

{-x(x+3a) / (x-3a)}·{(x-3a)(x-a)} = -x(x+3a)(x-a) (= -x³-2ax²+3ax)

Answer: -x(x+3a)(x-a)

by
edited

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